Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
88 | 93 | 60 |
22 | 14 | 62 |
27 | 26 | 79 |
Subtract row minima
We subtract the row minimum from each row:
28 | 33 | 0 | (-60) |
8 | 0 | 48 | (-14) |
1 | 0 | 53 | (-26) |
Subtract column minima
We subtract the column minimum from each column:
27 | 33 | 0 |
7 | 0 | 48 |
0 | 0 | 53 |
(-1) |
Cover all zeros with a minimum number of lines
There are 3 lines required to cover all zeros:
27 | 33 | 0 | x |
7 | 0 | 48 | x |
0 | 0 | 53 | x |
The optimal assignment
Because there are 3 lines required, the zeros cover an optimal assignment:
27 | 33 | 0 |
7 | 0 | 48 |
0 | 0 | 53 |
This corresponds to the following optimal assignment in the original cost matrix:
88 | 93 | 60 |
22 | 14 | 62 |
27 | 26 | 79 |
The optimal value equals 101.
HungarianAlgorithm.com © 2013-2024