Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
49 | 31 | 45 | 78 |
79 | 51 | 46 | 91 |
36 | 92 | 50 | 29 |
19 | 93 | 64 | 3 |
Subtract row minima
We subtract the row minimum from each row:
18 | 0 | 14 | 47 | (-31) |
33 | 5 | 0 | 45 | (-46) |
7 | 63 | 21 | 0 | (-29) |
16 | 90 | 61 | 0 | (-3) |
Subtract column minima
We subtract the column minimum from each column:
11 | 0 | 14 | 47 |
26 | 5 | 0 | 45 |
0 | 63 | 21 | 0 |
9 | 90 | 61 | 0 |
(-7) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
11 | 0 | 14 | 47 | x |
26 | 5 | 0 | 45 | x |
0 | 63 | 21 | 0 | x |
9 | 90 | 61 | 0 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
11 | 0 | 14 | 47 |
26 | 5 | 0 | 45 |
0 | 63 | 21 | 0 |
9 | 90 | 61 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
49 | 31 | 45 | 78 |
79 | 51 | 46 | 91 |
36 | 92 | 50 | 29 |
19 | 93 | 64 | 3 |
The optimal value equals 116.
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