Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
85 | 80 | 71 |
4 | 61 | 52 |
23 | 95 | 2 |
Subtract row minima
We subtract the row minimum from each row:
14 | 9 | 0 | (-71) |
0 | 57 | 48 | (-4) |
21 | 93 | 0 | (-2) |
Subtract column minima
We subtract the column minimum from each column:
14 | 0 | 0 |
0 | 48 | 48 |
21 | 84 | 0 |
(-9) |
Cover all zeros with a minimum number of lines
There are 3 lines required to cover all zeros:
14 | 0 | 0 | x |
0 | 48 | 48 | x |
21 | 84 | 0 | x |
The optimal assignment
Because there are 3 lines required, the zeros cover an optimal assignment:
14 | 0 | 0 |
0 | 48 | 48 |
21 | 84 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
85 | 80 | 71 |
4 | 61 | 52 |
23 | 95 | 2 |
The optimal value equals 86.
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