Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
75 | 29 | 63 |
43 | 49 | 44 |
9 | 46 | 88 |
Subtract row minima
We subtract the row minimum from each row:
46 | 0 | 34 | (-29) |
0 | 6 | 1 | (-43) |
0 | 37 | 79 | (-9) |
Subtract column minima
We subtract the column minimum from each column:
46 | 0 | 33 |
0 | 6 | 0 |
0 | 37 | 78 |
(-1) |
Cover all zeros with a minimum number of lines
There are 3 lines required to cover all zeros:
46 | 0 | 33 | x |
0 | 6 | 0 | x |
0 | 37 | 78 | x |
The optimal assignment
Because there are 3 lines required, the zeros cover an optimal assignment:
46 | 0 | 33 |
0 | 6 | 0 |
0 | 37 | 78 |
This corresponds to the following optimal assignment in the original cost matrix:
75 | 29 | 63 |
43 | 49 | 44 |
9 | 46 | 88 |
The optimal value equals 82.
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