Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
68 | 61 | 91 | 10 |
86 | 90 | 70 | 78 |
76 | 94 | 52 | 87 |
77 | 33 | 77 | 76 |
Subtract row minima
We subtract the row minimum from each row:
58 | 51 | 81 | 0 | (-10) |
16 | 20 | 0 | 8 | (-70) |
24 | 42 | 0 | 35 | (-52) |
44 | 0 | 44 | 43 | (-33) |
Subtract column minima
We subtract the column minimum from each column:
42 | 51 | 81 | 0 |
0 | 20 | 0 | 8 |
8 | 42 | 0 | 35 |
28 | 0 | 44 | 43 |
(-16) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
42 | 51 | 81 | 0 | x |
0 | 20 | 0 | 8 | x |
8 | 42 | 0 | 35 | x |
28 | 0 | 44 | 43 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
42 | 51 | 81 | 0 |
0 | 20 | 0 | 8 |
8 | 42 | 0 | 35 |
28 | 0 | 44 | 43 |
This corresponds to the following optimal assignment in the original cost matrix:
68 | 61 | 91 | 10 |
86 | 90 | 70 | 78 |
76 | 94 | 52 | 87 |
77 | 33 | 77 | 76 |
The optimal value equals 181.
HungarianAlgorithm.com © 2013-2025