Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
62 | 69 | 95 |
26 | 73 | 65 |
98 | 11 | 79 |
Subtract row minima
We subtract the row minimum from each row:
0 | 7 | 33 | (-62) |
0 | 47 | 39 | (-26) |
87 | 0 | 68 | (-11) |
Subtract column minima
We subtract the column minimum from each column:
0 | 7 | 0 |
0 | 47 | 6 |
87 | 0 | 35 |
(-33) |
Cover all zeros with a minimum number of lines
There are 3 lines required to cover all zeros:
0 | 7 | 0 | x |
0 | 47 | 6 | x |
87 | 0 | 35 | x |
The optimal assignment
Because there are 3 lines required, the zeros cover an optimal assignment:
0 | 7 | 0 |
0 | 47 | 6 |
87 | 0 | 35 |
This corresponds to the following optimal assignment in the original cost matrix:
62 | 69 | 95 |
26 | 73 | 65 |
98 | 11 | 79 |
The optimal value equals 132.
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