Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
47 | 42 | 60 | 26 |
50 | 78 | 63 | 17 |
71 | 50 | 15 | 84 |
37 | 47 | 59 | 31 |
Subtract row minima
We subtract the row minimum from each row:
21 | 16 | 34 | 0 | (-26) |
33 | 61 | 46 | 0 | (-17) |
56 | 35 | 0 | 69 | (-15) |
6 | 16 | 28 | 0 | (-31) |
Subtract column minima
We subtract the column minimum from each column:
15 | 0 | 34 | 0 |
27 | 45 | 46 | 0 |
50 | 19 | 0 | 69 |
0 | 0 | 28 | 0 |
(-6) | (-16) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
15 | 0 | 34 | 0 | x |
27 | 45 | 46 | 0 | x |
50 | 19 | 0 | 69 | x |
0 | 0 | 28 | 0 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
15 | 0 | 34 | 0 |
27 | 45 | 46 | 0 |
50 | 19 | 0 | 69 |
0 | 0 | 28 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
47 | 42 | 60 | 26 |
50 | 78 | 63 | 17 |
71 | 50 | 15 | 84 |
37 | 47 | 59 | 31 |
The optimal value equals 111.
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