Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
26 | 30 | 82 | 76 |
56 | 16 | 33 | 86 |
81 | 26 | 47 | 18 |
39 | 52 | 35 | 58 |
Subtract row minima
We subtract the row minimum from each row:
0 | 4 | 56 | 50 | (-26) |
40 | 0 | 17 | 70 | (-16) |
63 | 8 | 29 | 0 | (-18) |
4 | 17 | 0 | 23 | (-35) |
Subtract column minima
Because each column contains a zero, subtracting column minima has no effect.
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
0 | 4 | 56 | 50 | x |
40 | 0 | 17 | 70 | x |
63 | 8 | 29 | 0 | x |
4 | 17 | 0 | 23 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
0 | 4 | 56 | 50 |
40 | 0 | 17 | 70 |
63 | 8 | 29 | 0 |
4 | 17 | 0 | 23 |
This corresponds to the following optimal assignment in the original cost matrix:
26 | 30 | 82 | 76 |
56 | 16 | 33 | 86 |
81 | 26 | 47 | 18 |
39 | 52 | 35 | 58 |
The optimal value equals 95.
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