Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
47 | 66 | 1 | 10 |
87 | 59 | 46 | 47 |
84 | 80 | 54 | 97 |
62 | 13 | 14 | 18 |
Subtract row minima
We subtract the row minimum from each row:
46 | 65 | 0 | 9 | (-1) |
41 | 13 | 0 | 1 | (-46) |
30 | 26 | 0 | 43 | (-54) |
49 | 0 | 1 | 5 | (-13) |
Subtract column minima
We subtract the column minimum from each column:
16 | 65 | 0 | 8 |
11 | 13 | 0 | 0 |
0 | 26 | 0 | 42 |
19 | 0 | 1 | 4 |
(-30) | (-1) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
16 | 65 | 0 | 8 | x |
11 | 13 | 0 | 0 | x |
0 | 26 | 0 | 42 | x |
19 | 0 | 1 | 4 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
16 | 65 | 0 | 8 |
11 | 13 | 0 | 0 |
0 | 26 | 0 | 42 |
19 | 0 | 1 | 4 |
This corresponds to the following optimal assignment in the original cost matrix:
47 | 66 | 1 | 10 |
87 | 59 | 46 | 47 |
84 | 80 | 54 | 97 |
62 | 13 | 14 | 18 |
The optimal value equals 145.
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