Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
97 | 98 | 23 | 64 |
25 | 82 | 80 | 87 |
49 | 44 | 41 | 4 |
84 | 17 | 18 | 94 |
Subtract row minima
We subtract the row minimum from each row:
74 | 75 | 0 | 41 | (-23) |
0 | 57 | 55 | 62 | (-25) |
45 | 40 | 37 | 0 | (-4) |
67 | 0 | 1 | 77 | (-17) |
Subtract column minima
Because each column contains a zero, subtracting column minima has no effect.
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
74 | 75 | 0 | 41 | x |
0 | 57 | 55 | 62 | x |
45 | 40 | 37 | 0 | x |
67 | 0 | 1 | 77 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
74 | 75 | 0 | 41 |
0 | 57 | 55 | 62 |
45 | 40 | 37 | 0 |
67 | 0 | 1 | 77 |
This corresponds to the following optimal assignment in the original cost matrix:
97 | 98 | 23 | 64 |
25 | 82 | 80 | 87 |
49 | 44 | 41 | 4 |
84 | 17 | 18 | 94 |
The optimal value equals 69.
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