Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
73 | 7 | 43 | 93 |
7 | 7 | 57 | 40 |
37 | 50 | 27 | 67 |
50 | 9 | 77 | 28 |
Subtract row minima
We subtract the row minimum from each row:
66 | 0 | 36 | 86 | (-7) |
0 | 0 | 50 | 33 | (-7) |
10 | 23 | 0 | 40 | (-27) |
41 | 0 | 68 | 19 | (-9) |
Subtract column minima
We subtract the column minimum from each column:
66 | 0 | 36 | 67 |
0 | 0 | 50 | 14 |
10 | 23 | 0 | 21 |
41 | 0 | 68 | 0 |
(-19) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
66 | 0 | 36 | 67 | x |
0 | 0 | 50 | 14 | x |
10 | 23 | 0 | 21 | x |
41 | 0 | 68 | 0 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
66 | 0 | 36 | 67 |
0 | 0 | 50 | 14 |
10 | 23 | 0 | 21 |
41 | 0 | 68 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
73 | 7 | 43 | 93 |
7 | 7 | 57 | 40 |
37 | 50 | 27 | 67 |
50 | 9 | 77 | 28 |
The optimal value equals 69.
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