Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
19 | 83 | 38 | 95 |
81 | 55 | 92 | 91 |
28 | 93 | 2 | 87 |
26 | 3 | 40 | 25 |
Subtract row minima
We subtract the row minimum from each row:
0 | 64 | 19 | 76 | (-19) |
26 | 0 | 37 | 36 | (-55) |
26 | 91 | 0 | 85 | (-2) |
23 | 0 | 37 | 22 | (-3) |
Subtract column minima
We subtract the column minimum from each column:
0 | 64 | 19 | 54 |
26 | 0 | 37 | 14 |
26 | 91 | 0 | 63 |
23 | 0 | 37 | 0 |
(-22) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
0 | 64 | 19 | 54 | x |
26 | 0 | 37 | 14 | x |
26 | 91 | 0 | 63 | x |
23 | 0 | 37 | 0 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
0 | 64 | 19 | 54 |
26 | 0 | 37 | 14 |
26 | 91 | 0 | 63 |
23 | 0 | 37 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
19 | 83 | 38 | 95 |
81 | 55 | 92 | 91 |
28 | 93 | 2 | 87 |
26 | 3 | 40 | 25 |
The optimal value equals 101.
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