Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
64 | 90 | 9 | 42 |
15 | 55 | 33 | 58 |
25 | 26 | 17 | 91 |
58 | 53 | 18 | 17 |
Subtract row minima
We subtract the row minimum from each row:
55 | 81 | 0 | 33 | (-9) |
0 | 40 | 18 | 43 | (-15) |
8 | 9 | 0 | 74 | (-17) |
41 | 36 | 1 | 0 | (-17) |
Subtract column minima
We subtract the column minimum from each column:
55 | 72 | 0 | 33 |
0 | 31 | 18 | 43 |
8 | 0 | 0 | 74 |
41 | 27 | 1 | 0 |
(-9) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
55 | 72 | 0 | 33 | x |
0 | 31 | 18 | 43 | x |
8 | 0 | 0 | 74 | x |
41 | 27 | 1 | 0 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
55 | 72 | 0 | 33 |
0 | 31 | 18 | 43 |
8 | 0 | 0 | 74 |
41 | 27 | 1 | 0 |
This corresponds to the following optimal assignment in the original cost matrix:
64 | 90 | 9 | 42 |
15 | 55 | 33 | 58 |
25 | 26 | 17 | 91 |
58 | 53 | 18 | 17 |
The optimal value equals 67.
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