Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
62 | 77 | 96 | 64 |
42 | 82 | 69 | 30 |
75 | 47 | 11 | 31 |
44 | 9 | 93 | 26 |
Subtract row minima
We subtract the row minimum from each row:
0 | 15 | 34 | 2 | (-62) |
12 | 52 | 39 | 0 | (-30) |
64 | 36 | 0 | 20 | (-11) |
35 | 0 | 84 | 17 | (-9) |
Subtract column minima
Because each column contains a zero, subtracting column minima has no effect.
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
0 | 15 | 34 | 2 | x |
12 | 52 | 39 | 0 | x |
64 | 36 | 0 | 20 | x |
35 | 0 | 84 | 17 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
0 | 15 | 34 | 2 |
12 | 52 | 39 | 0 |
64 | 36 | 0 | 20 |
35 | 0 | 84 | 17 |
This corresponds to the following optimal assignment in the original cost matrix:
62 | 77 | 96 | 64 |
42 | 82 | 69 | 30 |
75 | 47 | 11 | 31 |
44 | 9 | 93 | 26 |
The optimal value equals 112.
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