Fill in the cost matrix of an assignment problem and click on 'Solve'. The optimal assignment will be determined and a step by step explanation of the hungarian algorithm will be given.
Fill in the cost matrix (random cost matrix):
Size: 3x3 4x4 5x5 6x6 7x7 8x8 9x9 10x10
This is the original cost matrix:
56 | 6 | 84 | 46 |
69 | 6 | 22 | 22 |
52 | 8 | 16 | 61 |
32 | 67 | 60 | 82 |
Subtract row minima
We subtract the row minimum from each row:
50 | 0 | 78 | 40 | (-6) |
63 | 0 | 16 | 16 | (-6) |
44 | 0 | 8 | 53 | (-8) |
0 | 35 | 28 | 50 | (-32) |
Subtract column minima
We subtract the column minimum from each column:
50 | 0 | 70 | 24 |
63 | 0 | 8 | 0 |
44 | 0 | 0 | 37 |
0 | 35 | 20 | 34 |
(-8) | (-16) |
Cover all zeros with a minimum number of lines
There are 4 lines required to cover all zeros:
50 | 0 | 70 | 24 | x |
63 | 0 | 8 | 0 | x |
44 | 0 | 0 | 37 | x |
0 | 35 | 20 | 34 | x |
The optimal assignment
Because there are 4 lines required, the zeros cover an optimal assignment:
50 | 0 | 70 | 24 |
63 | 0 | 8 | 0 |
44 | 0 | 0 | 37 |
0 | 35 | 20 | 34 |
This corresponds to the following optimal assignment in the original cost matrix:
56 | 6 | 84 | 46 |
69 | 6 | 22 | 22 |
52 | 8 | 16 | 61 |
32 | 67 | 60 | 82 |
The optimal value equals 76.
HungarianAlgorithm.com © 2013-2025